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AP Physics 1 Formula Sheet: Study Summary by Unit

Physics formula sheetsAP Physics 1Algebra basedUpdated 1 Nov 2026

∑F⃗=ma⃗\sum \vec{F} = m\vec{a}
where
  • ΣF net (resultant) force N
  • m mass of the object or system kg
  • a acceleration of the center of mass m/s²

This AP Physics 1 formula sheet is a study summary of the equations the course leans on, grouped by unit and led by Newton's second law, ∑F=ma\sum F = ma. It is not the official sheet. The exam board provides its own equation sheet and table of constants for the exam, with its own layout and wording, and that is the version you will see on test day.

Use this page to learn what each symbol means, which unit it carries, and when an equation is allowed. The symbols follow US textbooks: v0v_0 for initial velocity and Δx\Delta x for displacement, where Indian books would write u and s. For the other courses, see the AP Physics formula sheets hub.

Quick facts

  • What this is

    A study summary, not the official exam sheet
  • Official sheet

    Provided by the exam board with the exam
  • Most used

    ∑F=ma\sum F = ma
  • Math level

    Algebra and trigonometry, no calculus
  • Units covered

    Kinematics, dynamics, energy, momentum, rotation, oscillations, fluids
  • Symbols

    US style: v0v_0, Δx\Delta x, Δy\Delta y

How to use an AP Physics 1 formula sheet well

An exam equation sheet saves you from memorising every line, but it does not tell you which line to use, what the symbols stand for in a given setup, or when a relation stops being true. Those three skills are what the free response questions test.

  • Learn the conditions. The kinematics equations need constant acceleration. Conservation of momentum needs zero net external force on the system.
  • Learn the definitions the sheet leaves short. Know that impulse is the area under a force against time graph and that work is the area under a force against position graph.
  • Practise with the official layout. Download the current sheet from the exam board and keep it beside you while you do practice questions, so finding a line takes seconds.

The unit names below follow the current course outline. Check your teacher's outline in case the order differs.

Unit 1: Kinematics

Motion equations for constant acceleration
FormulaWhat it givesSI unitMore on this site
vx=vx0+axtv_x = v_{x0} + a_x tvelocity after time tm/sFinal velocity
x=x0+vx0t+12axt2x = x_0 + v_{x0}t + \frac{1}{2}a_x t^2position after time tmDisplacement
vx2=vx02+2ax(x−x0)v_x^2 = v_{x0}^2 + 2a_x(x - x_0)velocity without needing the timem/sEquations of motion
vˉ=ΔxΔt\bar{v} = \frac{\Delta x}{\Delta t}average velocitym/sAverage velocity
aˉ=ΔvΔt\bar{a} = \frac{\Delta v}{\Delta t}average accelerationm/s²Acceleration

For projectiles, apply these separately to x (with ax=0a_x = 0) and y (with ay=−ga_y = -g). The full chain of ideas is on the kinematics hub.

Units 2 and 3: Force, dynamics, work, energy and power

Force and energy relations
FormulaWhat it givesSI unitMore on this site
∑F=ma\sum F = maacceleration from the net forceNNet force
Fg=mgF_g = mgweight near EarthNWeight
fk=μkFNf_k = \mu_k F_N, fs≤μsFNf_s \le \mu_s F_Nkinetic and static frictionNFriction force
Fs=−k ΔxF_s = -k\,\Delta xspring force (Hooke's law)NSpring force
Fg=Gm1m2r2F_g = \frac{G m_1 m_2}{r^2}gravitational attractionNGravitation
ac=v2ra_c = \frac{v^2}{r}centripetal accelerationm/s²Centripetal acceleration
K=12mv2K = \frac{1}{2}mv^2kinetic energyJKinetic energy
W=Fdcos⁡θW = Fd\cos\thetawork by a constant forceJWork
ΔUg=mg Δy\Delta U_g = mg\,\Delta ygravitational potential energy changeJPotential energy
Us=12k Δx2U_s = \frac{1}{2}k\,\Delta x^2elastic energy in a springJSpring energy
UG=−Gm1m2rU_G = -\frac{G m_1 m_2}{r}potential energy of two masses a distance r apartJGravitation
P=ΔEΔt=Fvcos⁡θP = \frac{\Delta E}{\Delta t} = Fv\cos\thetapower, the rate of energy transferWWork and energy

Example: one cart, three units

A 2.0 kg cart starts from rest on a level track. A net force of 6.0 N pushes it for 4.0 s. Find its acceleration, final speed and kinetic energy, then check with work.

a=6.02.0=3.0 m/s2a = \frac{6.0}{2.0} = 3.0\ \text{m/s}^2, and v=0+(3.0)(4.0)=12 m/sv = 0 + (3.0)(4.0) = 12\ \text{m/s}.

K=12(2.0)(12)2=144 JK = \frac{1}{2}(2.0)(12)^2 = 144\ \text{J}

Check: distance Δx=12(3.0)(4.0)2=24 m\Delta x = \frac{1}{2}(3.0)(4.0)^2 = 24\ \text{m}, so work W=(6.0)(24)=144 JW = (6.0)(24) = 144\ \text{J}. The work energy theorem holds, and the answer is about 140 J to two significant figures.

Unit 4: Linear momentum

Momentum and impulse
FormulaWhat it givesSI unitMore on this site
p⃗=mv⃗\vec{p} = m\vec{v}momentum of one objectkg m/sMomentum
J⃗=F⃗avg Δt=Δp⃗\vec{J} = \vec{F}_{avg}\,\Delta t = \Delta\vec{p}impulse and its effectN sImpulse
∑mv⃗i=∑mv⃗f\sum m\vec{v}_i = \sum m\vec{v}_fconservation for an isolated systemkg m/sConservation of momentum
v⃗cm=∑mv⃗∑m\vec{v}_{cm} = \frac{\sum m\vec{v}}{\sum m}velocity of the center of massm/sCenter of mass

Momentum is conserved in every collision when the system is isolated. Kinetic energy is conserved only in elastic collisions. A question that says the objects stick together is telling you it is perfectly inelastic.

Units 5 and 6: Torque, rotation and rotating systems

Rotational equations, the twins of the linear ones
FormulaWhat it givesSI unitMore on this site
ω=ω0+αt\omega = \omega_0 + \alpha tangular velocity after time trad/sAngular velocity
θ=θ0+ω0t+12αt2\theta = \theta_0 + \omega_0 t + \frac{1}{2}\alpha t^2angle turnedradAngular acceleration
v=rωv = r\omega, aT=rαa_T = r\alphalink between linear and angularm/s, m/s²Tangential acceleration
τ=rFsin⁡θ\tau = rF\sin\thetatorque about an axisN mTorque
α=∑τI\alpha = \frac{\sum \tau}{I}angular acceleration from net torquerad/s²Rotation hub
I=∑mr2I = \sum m r^2, I′=Icm+Md2I' = I_{cm} + Md^2rotational inertia and the parallel axis theoremkg m²Moment of inertia
K=12Iω2K = \frac{1}{2}I\omega^2rotational kinetic energyJKinetic energy
L=IωL = I\omega, ΔL=τ Δt\Delta L = \tau\,\Delta tangular momentum and angular impulsekg m²/sAngular momentum

For rolling without slipping, vcm=rωv_{cm} = r\omega and the total kinetic energy is the translational part plus the rotational part. A rolling ball reaches the bottom of a ramp slower than a frictionless sliding block because some energy goes into spin.

Units 7 and 8: Oscillations and fluids

Simple harmonic motion and fluid relations
FormulaWhat it givesSI unitMore on this site
T=1fT = \frac{1}{f}period from frequencysPeriod
Ts=2πmkT_s = 2\pi\sqrt{\frac{m}{k}}period of a mass on a springsFrequency
Tp=2πℓgT_p = 2\pi\sqrt{\frac{\ell}{g}}period of a pendulum at small anglessPeriod
x=Acos⁡(2πft)x = A\cos(2\pi f t)position in SHM, starting at the maximummAmplitude
ρ=mV\rho = \frac{m}{V}densitykg/m³Density
P=FAP = \frac{F}{A}, P=P0+ρghP = P_0 + \rho g hpressure and pressure at depthPaPressure
Fb=ρVgF_b = \rho V gbuoyant force (fluid density, displaced volume)NBuoyant force
A1v1=A2v2A_1 v_1 = A_2 v_2continuity for an incompressible fluidm³/sFluids hub
P1+ρgy1+12ρv12=P2+ρgy2+12ρv22P_1 + \rho g y_1 + \frac{1}{2}\rho v_1^2 = P_2 + \rho g y_2 + \frac{1}{2}\rho v_2^2Bernoulli's equation along a streamlinePaFluids hub

Neither period formula depends on amplitude. The pendulum period does not depend on the bob mass either, while the spring period does not depend on g.

Mistakes the formula sheet for AP Physics 1 cannot prevent

  • Using a net force equation with one force. ∑F=ma\sum F = ma needs the vector sum of every force, so draw a free body diagram first.
  • Forgetting the radian mode. v=rωv = r\omega and aT=rαa_T = r\alpha only work with angles in radians.
  • Applying energy conservation with friction present. Friction turns mechanical energy into thermal energy, so include its work.
  • Using the wrong density in buoyancy. Fb=ρVgF_b = \rho V g uses the fluid density, not the density of the object.

When the course moves on to circuits, waves and optics, continue with the AP Physics 2 formula sheet. If you want the calculus version of mechanics, compare with the AP Physics C mechanics sheet.

Frequently asked questions

Is this the official AP Physics 1 formula sheet?

No. This page is a study summary written to help you learn the equations. The exam board publishes and provides the official equation sheet, so practise with that version before the exam.

Do you get a formula sheet for AP Physics 1 in the exam?

Yes, the exam board provides an equation sheet with a table of constants. It lists equations but does not explain when each one applies, so you still need to know the conditions.

What should I memorise even with a physics 1 formula sheet?

Learn the meaning of every symbol, the conditions for each equation and the definitions behind the graphs. Also learn how to draw free body diagrams and energy bar charts, since no sheet gives those.

What is the difference between the AP Physics 1 and AP Physics C sheets?

AP Physics 1 uses algebra and trigonometry. AP Physics C mechanics covers similar topics but writes many relations with derivatives and integrals, such as force as the rate of change of momentum.

Which value of g should I use in AP Physics 1?

Use 9.8 m/s² unless the question or the constants table says otherwise. Keep a few significant figures through the working and round at the end.