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Permittivity of Free Space Dimensional Formula

Dimensional formulas of physical quantitiesClass 12ElectrostaticsUpdated 1 Nov 2026

[ε0]=[M−1L−3T4I2][\varepsilon_0] = [M^{-1} L^{-3} T^{4} I^{2}]
SI unit
C²/(N m²) or F/m
Dimensions
[M⁻¹ L⁻³ T⁴ I²]
where
  • M dimension of mass kg
  • L dimension of length m
  • T dimension of time s
  • I dimension of electric current A

Written with current as the fourth base quantity, the permittivity of free space dimensional formula comes out as [M⁻¹ L⁻³ T⁴ I²]. It is one of the few brackets in Class 12 physics where mass carries a negative power and time a power as high as four.

The constant ε₀ (epsilon nought) appears in Coulomb's law, where it sets how strongly two charges push or pull through a vacuum. Its value is 8.854 × 10⁻¹² C²/(N m²). Because charge is not a base quantity in SI, the derivation first rewrites charge as current times time. Below you will find that working, the unit F/m, a check with the speed of light and capacitance, and the slips. The force law itself is on the electrostatic force formula page.

Quick facts

  • Dimensional formula

    [M⁻¹ L⁻³ T⁴ I²]
  • Defining law

    Coulomb's law, F=q1q24πε0r2F = \frac{q_1 q_2}{4\pi\varepsilon_0 r^{2}}
  • Value

    8.854 × 10⁻¹² C²/(N m²)
  • SI unit

    C²/(N m²) = F/m
  • Related constant

    1/(4πε₀) = 8.99 × 10⁹ N m²/C²
  • Chapter

    Electric charges and fields, Class 12

Deriving the permittivity of free space dimensional formula

  1. Coulomb\'s law: F=q1q24πε0r2F = \frac{q_1 q_2}{4\pi\varepsilon_0 r^{2}}, so ε0=q1q24πFr2\varepsilon_0 = \frac{q_1 q_2}{4\pi F r^{2}}.
  2. Since a charge equals a current flowing for a time (q = It), each charge is [IT] and the product q₁q₂ is [I²T²].
  3. The bottom: force [MLT⁻²] times r² [L²] gives [ML³T⁻²]; 4π has no dimensions.
  4. Divide: [I²T²] ÷ [ML³T⁻²]. Mass goes to M⁻¹, length to L⁻³, time to T²⁺² = T⁴, current stays I².

That completes the bracket for ε₀. The step that trips most students is the time power: T² from the charges and T⁺² from flipping the T⁻² of force add to T⁴. For charge alone, see the charge derivation.

Three ways to write the unit

Converted letter by letter, ε₀ is measured in kg⁻¹ m⁻³ s⁴ A². Few people write it like that; it is usually grouped in one of two tidier ways.

Equivalent units for ε₀
UnitWhere it comes from
C²/(N m²)Rearranging Coulomb's law
F/m (farad per metre)From C = ε₀A/d for a capacitor
kg⁻¹ m⁻³ s⁴ A²Straight from the dimensions

All three are the same unit. F/m is the neatest and is what most data tables print. The constant 1/(4πε₀) = 8.99 × 10⁹ N m²/C² has the inverse bracket, [M L³ T⁻⁴ I⁻²].

Permittivity of a medium and the dielectric constant

Permittivity of any material shares the bracket. Relative permittivity, also called the dielectric constant, is the ratio ε/ε₀, so it has no dimensions and no unit.

Permittivity and related quantities
QuantityRelationDimensions
Permittivity of free space ε₀From Coulomb's law[M⁻¹L⁻³T⁴I²]
Permittivity of a medium εε = εᵣε₀[M⁻¹L⁻³T⁴I²]
Dielectric constant εᵣε ÷ ε₀dimensionless
Capacitance Cε₀ × length[M⁻¹L⁻²T⁴I²]

The last row is why the farad per metre works as a unit: capacitance divided by a length gives permittivity. See the capacitance page for C on its own.

Two checks with electric constants

Check: the speed of light c = 1/√(μ₀ε₀)

Permeability of free space: μ₀ is [MLT⁻²I⁻²]. Multiply by ε₀, [M⁻¹L⁻³T⁴I²].

M cancels, L goes to L¹⁻³ = L⁻², T to T⁻²⁺⁴ = T², I cancels. So μ₀ε₀ is [L⁻²T²].

One over its square root is [LT⁻¹], a speed. The relation passes, and it links ε₀ to the permeability of free space.

Check: parallel plate capacitance C = ε₀A/d

ε₀ times area over distance: [M⁻¹L⁻³T⁴I²] × [L²] ÷ [L] = [M⁻¹L⁻²T⁴I²].

That is the bracket of capacitance, so the formula is consistent.

Where marks are lost

  • Forgetting to square the charge. Two charges multiply, so current and time each appear squared before you flip the force.
  • Writing T⁻⁴ or T². The force in the denominator brings T⁻², which becomes +2 when inverted, added to the +2 from charge.
  • Giving εᵣ a unit. Relative permittivity is a pure ratio.
  • Using an old charge based system without saying so. Some older books treat charge Q as a base quantity and write [M⁻¹L⁻³T²Q²]. In SI, with current as base, the answer is [M⁻¹L⁻³T⁴I²].

Electric and magnetic constants are grouped with the other brackets on the dimensional formulas page.

Frequently asked questions

Why does mass have a negative power in ε₀?

Force sits in the denominator when ε₀ is made the subject of Coulomb's law. Force carries M¹, so ε₀ ends up with M⁻¹.

What is the dimensional formula of permittivity of a medium?

It equals that of ε₀, [M⁻¹ L⁻³ T⁴ I²], because the medium's permittivity is just a dimensionless number times ε₀.

In which SI unit is ε₀ given?

In C²/(N m²), or equivalently farad per metre, F/m. Its value is 8.854 × 10⁻¹² in either.

Does the dielectric constant have dimensions?

No. The dielectric constant is the ratio of two permittivities, so all powers cancel.

How are ε₀ and μ₀ connected?

Their product is one over the speed of light squared, μ₀ε₀ = 1/c². In dimensions, [L⁻²T²].