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Dimensional Formula of Tension

Dimensional formulas of physical quantitiesClass 11Units and dimensionsUpdated 1 Nov 2026

[T]=[M1L1T−2][T] = [M^{1}L^{1}T^{-2}]
SI unit
newton (N) = kg m s⁻²
Dimensions
[M¹ L¹ T⁻²]
where
  • M dimension of mass kg
  • L dimension of length m
  • T dimension of time s

The dimensional formula of tension is [M¹ L¹ T⁻²], written in short as [MLT⁻²]. Tension is the pulling force that a string, rope, cable or chain exerts on whatever is tied to it, so it carries exactly the same dimensions as every other force.

One small warning before you start. The letter T is used twice in this topic: once as the symbol for tension and once as the dimension of time. Read the bracket [M L T⁻²] as mass, length and time, never as "tension to the power minus 2". The full set of tension formulas lives on the tension force formula page.

Quick facts

  • Dimensional formula

    [M¹ L¹ T⁻²], or [MLT⁻²]
  • Defining formula

    T=mgT = mg for a hanging load at rest
  • SI unit

    newton (N), the same as kg m s⁻²
  • CGS unit

    dyne (1 N = 10⁵ dyne)
  • Type

    Vector along the string, directed away from the body
  • Not the same as

    Surface tension, which is [M¹ L⁰ T⁻²]

Hanging bucket derivation: dimensional formula of tension

Take the simplest case: a bucket of mass m hangs at rest from a rope. The rope must hold up the weight, so the tension equals the weight.

  1. Write the defining relation: T=mgT = mg.
  2. Mass is a base quantity, so [m]=[M][m] = [M].
  3. g is an acceleration, length per second per second: [g]=[LT−2][g] = [LT^{-2}].
  4. Multiply the two: [T]=[M][LT−2]=[MLT−2][T] = [M][LT^{-2}] = [MLT^{-2}], which in full form is [M¹ L¹ T⁻²].

If the bucket is pulled upward with acceleration a, the tension becomes T=m(g+a)T = m(g + a). Both g and a are accelerations, so the bracket (g+a)(g + a) still has dimensions [LT⁻²] and the result does not change. Adding two quantities is only allowed when they share dimensions, and here they do. The steps match the dimensional formula of force because tension is simply a force with a direction fixed by the string.

Reading the bracket as a unit

Swap each dimension for its SI base unit: M becomes kilogram, L becomes metre and T becomes second. The bracket [M¹ L¹ T⁻²] turns into kg m s⁻², which is the newton. That is why a tension in a lift cable, a guitar string or a tow rope is always quoted in newtons.

The same swap gives the CGS unit. With gram, centimetre and second you get g cm s⁻², the dyne. Since 1 kg is 1000 g and 1 m is 100 cm, one newton equals 1000×100=1051000 \times 100 = 10^{5} dyne. A crane cable under 2.0 × 10⁴ N therefore carries 2.0 × 10⁹ dyne.

Spring balances often read in kilogram-force. Multiply by 9.8 to get newtons before you use any formula.

Quantities that share the dimensions of tension

Forces with the bracket [M¹ L¹ T⁻²]
QuantityCommon formulaReason
TensionT=m(g+a)T = m(g + a)Pull of a string
WeightW=mgW = mgMass times acceleration
Normal reactionN=mgcos⁡θN = mg\cos\theta on an inclinecos θ is a pure number
Spring forceF=kxF = kx[MT⁻²] times [L]
Centripetal forcemv2r\frac{mv^2}{r}[M][L²T⁻²] over [L]

Because they match, you may add a tension to a weight in a free body equation. You may never add tension to surface tension, which is a force per unit length, [MT⁻²], or to pressure, which is force per area.

Dimensional check: wave speed on a stretched string

Example: show that v=T/μv = \sqrt{T/\mu} gives a speed, where μ is mass per unit length.

Linear mass density: [μ]=[M][L]=[ML−1][\mu] = \frac{[M]}{[L]} = [ML^{-1}].

Ratio: [T][μ]=[MLT−2][ML−1]=[L2T−2]\frac{[T]}{[\mu]} = \frac{[MLT^{-2}]}{[ML^{-1}]} = [L^{2}T^{-2}].

Square root: [LT−1][LT^{-1}], which is the dimension of velocity. The formula passes.

Example: a student writes the frequency of a string as f=12lTμf = \frac{1}{2l}\sqrt{T\mu}. Is it possible?

Inside the root: [MLT−2][ML−1]=[M2T−2][MLT^{-2}][ML^{-1}] = [M^{2}T^{-2}]. Root: [MT−1][MT^{-1}]. Dividing by length gives [ML−1T−1][ML^{-1}T^{-1}], not [T⁻¹]. The correct form has T divided by μ, not multiplied.

Slips students make with tension dimensions

  • Mixing up the two T's. Write tension as F or T in words and keep T inside brackets for time only.
  • Writing [MT⁻²]. That bracket belongs to surface tension and spring constant, not to the tension in a rope.
  • Thinking a massless string has no dimensions. The string has no mass, but the force it carries still has [MLT⁻²].
  • Dropping the minus sign on time. Seconds sit in the denominator, so the power is minus 2.

To compare tension with dozens of other quantities, open the dimensional formulas list, where every force sits in one row with the cable.

Frequently asked questions

What is the dimensional formula of tension?

Tension is a force, so the bracket you need is [M¹ L¹ T⁻²]. You can derive it from T = mg, mass [M] multiplied by the acceleration due to gravity [LT⁻²].

Is the dimension formula of tension the same as force?

Yes. Tension is one kind of force, transmitted by a string or cable, so it has the same bracket [MLT⁻²] and the same SI unit, the newton.

What is the difference between tension and surface tension dimensions?

Tension in a string is a force, [M¹ L¹ T⁻²]. Surface tension is force divided by length, so one power of L cancels and it becomes [M¹ L⁰ T⁻²], measured in N/m.

Which SI unit measures tension in a rope?

Rope and cable tension is measured in newtons. Put kilogram, metre and second in place of M, L and T and you get kg m s⁻², which is precisely what a newton stands for.

Does tension change its dimensions in an accelerating lift?

No. The value changes to m(g + a) going up or m(g − a) going down, but g and a are both accelerations, so the dimensions stay [MLT⁻²].