Skip to the content
Find a formula

Modulus of Rigidity Formula

Fluids and properties of matter formulasClass 11ShearUpdated 1 Nov 2026

G=F/Aθ=FLA ΔxG = \frac{F/A}{\theta} = \frac{F L}{A\,\Delta x}
SI unit
Pa (N/m²)
Dimensions
[M¹ L⁻¹ T⁻²]
where
  • G modulus of rigidity (shear modulus, also η or n) Pa
  • F tangential force on the top face N
  • A area of the face the force acts along m²
  • Δx sideways shift of the top face m
  • L distance between the fixed and moving faces m
  • θ shear strain, the angle of shear rad

The modulus of rigidity formula is G=shear stressshear strain=F/AθG = \frac{\text{shear stress}}{\text{shear strain}} = \frac{F/A}{\theta}. For a block whose top face slides a distance Δx over a height L, the shear strain is θ=ΔxL\theta = \frac{\Delta x}{L}, so G=FLA ΔxG = \frac{F L}{A\,\Delta x}. The modulus measures how strongly a solid resists a change of shape at constant volume.

You also see it called the shear modulus. NCERT writes G, while older Indian books use η or n; do not confuse that η with viscosity. Only solids have a modulus of rigidity, because a liquid simply flows when sheared. It is the third elastic modulus listed in the matter and fluids revision tables.

Quick facts

  • Formula

    G=F/Aθ=FLA ΔxG = \frac{F/A}{\theta} = \frac{F L}{A\,\Delta x}
  • SI unit

    pascal (Pa)
  • Dimensional formula

    [M¹ L⁻¹ T⁻²]
  • Other symbols

    η or n in some books
  • Link to Y

    Y=2G(1+ν)Y = 2G(1 + \nu)
  • Steel

    about 8 × 10¹⁰ Pa

Symbols in the modulus of rigidity formula

Quantities in G = FL / (A Δx)
SymbolMeaningSI unit
GGModulus of rigidityPa
FFForce parallel to the top faceN
AAArea of that face (the force lies in it)m²
Δx\Delta xHow far the top face moves sidewaysm
LLHeight of the block, at right angles to the shiftm
θ\thetaAngle of shear, ≈ΔxL\approx \frac{\Delta x}{L}rad

Push a thick book's cover sideways while the back cover stays flat on the desk. The pages slide, the spine tilts and the book becomes a slanted box with the same volume. That slanted shape is shear. The force acts along the face, so A is the area of the face being pushed, not a cross section at right angles to the force, which is where shear differs from tensile stress.

Worked examples

Example 1: a rubber mounting pad

A rubber pad has a top face 0.30 m × 0.30 m and a thickness of 5.0 cm. A horizontal force of 900 N moves the top face 2.0 mm relative to the bottom. Find the modulus of rigidity.

Shear stress: 9000.090=1.0×104 Pa\frac{900}{0.090} = 1.0\times10^4\ \text{Pa}. Shear strain: θ=2.0×10−30.050=0.040\theta = \frac{2.0\times10^{-3}}{0.050} = 0.040.

G=1.0×1040.040=2.5×105 PaG = \frac{1.0\times10^4}{0.040} = 2.5\times10^5\ \text{Pa}

Example 2: a steel cube barely moves

A steel cube of side 10 cm (G = 8.0 × 10¹⁰ Pa) has its bottom fixed. A force of 1.0 × 10⁵ N acts along its top face. Find the angle of shear and the shift of the top face.

Area of face: 0.10×0.10=0.010 m20.10 \times 0.10 = 0.010\ \text{m}^2, so the shear stress is 1.0×107 Pa1.0\times10^7\ \text{Pa}.

θ=1.0×1078.0×1010=1.25×10−4 rad\theta = \frac{1.0\times10^7}{8.0\times10^{10}} = 1.25\times10^{-4}\ \text{rad}

Shift: Δx=θL=1.25×10−4×0.10=1.25×10−5 m\Delta x = \theta L = 1.25\times10^{-4} \times 0.10 = 1.25\times10^{-5}\ \text{m}, about 0.013 mm.

For shear, the height L is measured at right angles to the force, between the fixed face and the moving face.

Typical values and how G relates to Y

Approximate modulus of rigidity of some solids
MaterialG in Pa
Steelabout 8 × 10¹⁰
Copperabout 4 × 10¹⁰
Aluminiumabout 2.5 × 10¹⁰
Glassabout 2.6 × 10¹⁰
Rubberabout 10⁵ to 10⁶

For most solids G is roughly a third to two fifths of Young's modulus, through Y=2G(1+ν)Y = 2G(1+\nu). Steel, with Y ≈ 2.0 × 10¹¹ Pa and ν ≈ 0.3, gives G ≈ 2.0 × 10¹¹ / 2.6 ≈ 7.7 × 10¹⁰ Pa, matching the table. For a side by side comparison of all three moduli, see the modulus of elasticity formula.

Where shear modulus matters

  • Twisting wires and shafts. The torque needed to twist a wire through an angle depends on G. Torsion pendulums and drive shafts are designed with it.
  • Earthquake waves. S waves are shear waves, and their speed is √(G/ρ). Liquids have G = 0, which is why S waves do not pass through Earth's liquid outer core.
  • Rubber mounts. A low G lets machinery rock slightly on its pads and absorbs vibration.

Mistakes to avoid

  • Using the area perpendicular to the force. In shear, the force lies along the face whose area you use.
  • Dividing Δx by the wrong length. Use the height between the faces, not the width of the face.
  • Giving θ in degrees. Shear strain is in radians.
  • Mixing η for rigidity with η for viscosity. Write G to stay clear.

Frequently asked questions

How do you write the modulus of rigidity formula?

G = shear stress / shear strain = (F/A) / θ. With θ = Δx / L for small shifts, G = FL / (AΔx).

What is the unit of modulus of rigidity?

The pascal (N/m²), the same as stress, because shear strain has no unit. Dimensions: [M¹ L⁻¹ T⁻²].

Is modulus of rigidity the same as shear modulus?

Yes. Both names describe the ratio of shear stress to shear strain; G is the usual symbol.

Why do liquids have no modulus of rigidity?

A liquid cannot hold a fixed shape. Any shear force, however small, makes it flow, so there is no steady shear strain to divide by.