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JEE Mains Physics Formula Sheet

Physics formula sheetsJEE MainClass 11 and 12Updated 1 Nov 2026

a=gsin⁡θ1+k2R2a = \frac{g\sin\theta}{1 + \frac{k^2}{R^2}}
where
  • a acceleration of the center of mass m/s²
  • g acceleration due to gravity m/s²
  • θ angle of the incline degree
  • k radius of gyration m
  • R radius of the rolling body m

This JEE mains physics formula sheet gathers results that turn long problems into short ones, such as the rolling acceleration a=gsin⁡θ1+(k/R)2a = \frac{g \sin\theta}{1 + (k/R)^2}. JEE Main physics draws on what you study in Classes 11 and 12, but its questions combine ideas, so the sheet stresses derived results, limiting cases and shortcuts on top of the textbook formulas.

Treat it as a physics formula sheet for JEE revision written for this site; it is not issued by the exam's conducting body, and JEE Main does not normally supply a formula sheet, so check the current information bulletin for the rules. The basics of each chapter are on the Class 11 list and the Class 12 sheet, and other courses are on the formula sheets hub.

Quick facts

  • Syllabus base

    Class 11 and Class 12 physics
  • Style

    Multi concept problems, numerical answers as well as options
  • Rolling result

    a=gsin⁡θ1+k2/R2a = \frac{g\sin\theta}{1 + k^2/R^2}
  • Error rule

    For Z = AᵖBᵠ, ΔZ/Z = pΔA/A + qΔB/B
  • Must know

    Calculus, vectors, graphs and dimensions
  • Handy values

    hc ≈ 1240 eV nm, 1 u ≈ 931.5 MeV/c²

Measurement, errors and dimensions

Units and measurement results
ResultWhen JEE uses itUnitExplained
ΔZZ=pΔAA+qΔBB\frac{\Delta Z}{Z} = p\frac{\Delta A}{A} + q\frac{\Delta B}{B}maximum fractional error of a power lawno unitDimensional formulas explained
[MaLbTc][M^a L^b T^c]checking or building a formula by dimensionsno unitForce dimensions explained
LC=1 MSD−1 VSD\text{LC} = 1\ \text{MSD} - 1\ \text{VSD}least count of a vernier calipermUnits explained

Example 1: error in g from a pendulum

A student finds g from g=4π2LT2g = \frac{4\pi^2 L}{T^2}. The length has a 1.0% error and the period a 0.5% error. What is the maximum percentage error in g?

Δgg=ΔLL+2ΔTT=1.0%+2(0.5%)=2.0%\frac{\Delta g}{g} = \frac{\Delta L}{L} + 2\frac{\Delta T}{T} = 1.0\% + 2(0.5\%) = 2.0\%.

Answer: 2.0%. The power of T doubles its share, which is why timing many oscillations improves the result.

Mechanics results worth memorising

Advanced mechanics
ResultWhen JEE uses itUnitExplained
a=ΔmM ga = \frac{\Delta m}{M}\,gAtwood machine, light pulley: Δm the mass difference, M the totalm/s²Tension explained
F=vreldmdtF = v_{rel}\frac{dm}{dt}thrust when mass is ejected (rockets, conveyor)NThrust explained
v=μsrgv = \sqrt{\mu_s rg}top speed on a flat circular roadm/sBanking explained
a=gsin⁡θ1+I/(mR2)a = \frac{g\sin\theta}{1 + I/(mR^2)}rolling without slipping down an inclinem/s²Radius of gyration explained
E=−GMm2rE = -\frac{GMm}{2r}total energy of a satellite in a circular orbitJOrbital velocity explained
T=2πr3GMT = 2\pi\sqrt{\frac{r^3}{GM}}orbital periodsSatellite period explained
vcm=m1v1+m2v2m1+m2v_{cm} = \frac{m_1v_1 + m_2v_2}{m_1 + m_2}center of mass velocity, unchanged with no external forcem/sCenter of mass explained

Example 2: which rolls fastest

A solid sphere rolls without slipping down a slope inclined at 37° (take sin 37° = 0.6). Find its acceleration, and compare with a ring.

For a solid sphere k2/R2=2/5k^2/R^2 = 2/5, so a=(9.8)(0.6)1.4=4.2 m/s2a = \frac{(9.8)(0.6)}{1.4} = 4.2\ \text{m/s}^2.

For a ring k2/R2=1k^2/R^2 = 1, so a=(9.8)(0.6)2=2.94 m/s2a = \frac{(9.8)(0.6)}{2} = 2.94\ \text{m/s}^2. Answer: 4.2 m/s² for the sphere; the ring, with more of its mass far from the axis, is slower.

Heat, thermodynamics and waves

Thermal physics and oscillations
ResultWhen JEE uses itUnitExplained
W=nRTln⁡V2V1W = nRT\ln\frac{V_2}{V_1}isothermal work done by an ideal gasJFirst law explained
PVγ=constantPV^\gamma = \text{constant}adiabatic change of an ideal gasPa m³ᵞThermodynamics explained
dTdt=−k(T−T0)\frac{dT}{dt} = -k(T - T_0)cooling of a hot bodyK/sNewton's law of cooling explained
f′=f v±vov∓vsf' = f\,\frac{v \pm v_o}{v \mp v_s}Doppler effect for soundHzSpeed of sound explained
v=γPρv = \sqrt{\frac{\gamma P}{\rho}}Laplace's result for sound through a gasm/sSound speed explained
I∝A2f2I \propto A^2 f^2intensity of a waveW/m²Intensity explained
In the Doppler formula, use the upper signs when source and observer move towards each other.

Electricity and magnetism on the jee mains physics formula sheet

Electrostatics, circuits, magnetism and AC
ResultWhen JEE uses itUnitExplained
C=ε0Ad−t+t/KC = \frac{\varepsilon_0 A}{d - t + t/K}capacitor partly filled with a slab of thickness tFCapacitance explained
q=q0(1−e−t/RC)q = q_0\left(1 - e^{-t/RC}\right)charging through a resistorCRC charging explained
f=qB2πmf = \frac{qB}{2\pi m}cyclotron frequencyHzLorentz force explained
μ⃗=NIA⃗\vec{\mu} = NI\vec{A}magnetic moment of a coilA m²Magnetic moment explained
cos⁡ϕ=RZ\cos\phi = \frac{R}{Z}power factor of an LCR circuitno unitImpedance explained
M=μ0n1n2πr12lM = \mu_0 n_1 n_2 \pi r_1^2 lmutual inductance of coaxial solenoids, inner radius r₁HMutual inductance explained

When a capacitor is connected to a battery and a slab is inserted, V stays fixed; when the battery is removed first, Q stays fixed. Decide which before you calculate energy changes.

Optics and modern physics

Light, atoms and nuclei
ResultWhen JEE uses itUnitExplained
n=sin⁡A+δm2sin⁡A2n = \frac{\sin\frac{A + \delta_m}{2}}{\sin\frac{A}{2}}refractive index from minimum deviation in a prismno unitAngle of deviation explained
P=P1+P2P = P_1 + P_2two thin lenses touching, with P = 1/F in dioptresm⁻¹Lens power explained
rn=(0.053 nm) n2Zr_n = (0.053\ \text{nm})\,\frac{n^2}{Z}Bohr orbit radiusmOrbital angular momentum explained
1λ=RZ2[1nf2−1ni2]\frac{1}{\lambda} = RZ^2\left[\frac{1}{n_f^2} - \frac{1}{n_i^2}\right]wavelength of a line, electron falling from nᵢ to n_fm⁻¹Spectral lines explained
λ=h2mK\lambda = \frac{h}{\sqrt{2mK}}de Broglie wavelength from kinetic energymDual nature explained

Silvered lens questions combine lens and mirror power; see silvering of a lens for the method.

How to revise physics for JEE with a formula sheet

  • Derive, then memorise. If you can derive the rolling result in two lines, you will not misremember it.
  • Learn limiting cases. Set m₂ = 0 in the Atwood result and you should get g.
  • Check units of options. It often eliminates two choices at once.
  • Keep a mistakes notebook. Note each formula you misapplied and why.

If you are also preparing for the medical entrance, the NEET physics formula sheet focuses on the NCERT core.

Frequently asked questions

Is a formula sheet given in JEE Main?

Students are generally expected to know the formulas, and no sheet is usually supplied. Check the current information bulletin for the rules of your attempt.

Which physics topics carry the most weight in JEE Main?

Mechanics, electricity and magnetism, and modern physics together make up much of the paper, but questions come from every chapter, so do not skip any.

Is this physics formula sheet for JEE Mains enough for JEE Advanced?

It covers the core results, but JEE Advanced asks deeper multi step problems. Use it as a base and add derivations and special cases.

How do I remember so many physics formulas for JEE?

Link them: rotation mirrors linear motion, electric and gravitational fields share inverse square forms, and many results are limiting cases of a general one. Practise daily with mixed problems.